A body is under the action of two equal and opposite forces, each of 10 N. The body is displaced by 5 m. The work done is

Options

A. `+50J`
B. `-50 J `
C. `100 J`
D. Zero

Explanation

To solve the problem, we need to calculate the work done on a body that is subjected to two equal and opposite forces. Here’s a step-by-step breakdown of the solution:

### Step 1: Understand the Forces Acting on the Body
The body is under the action of two equal and opposite forces, each of 10 N. This means:
- Force 1 (F1) = 10 N (acting in one direction)
- Force 2 (F2) = 10 N (acting in the opposite direction)

### Step 2: Calculate the Net Force
Since the forces are equal in magnitude and opposite in direction, the net force (F_net) acting on the body is:
\[ F_{\text{net}} = F1 - F2 = 10 \, \text{N} - 10 \, \text{N} = 0 \, \text{N} \]

### Step 3: Determine the Displacement
The body is displaced by a distance of 5 m. However, since the net force acting on the body is zero, we need to consider how this affects the work done.

### Step 4: Calculate the Work Done
The work done (W) is given by the formula:
\[ W = F_{\text{net}} \times d \]
Where:
- \( F_{\text{net}} \) is the net force acting on the body (which we calculated to be 0 N)
- \( d \) is the displacement (5 m)

Substituting the values:
\[ W = 0 \, \text{N} \times 5 \, \text{m} = 0 \, \text{J} \]

### Conclusion
The work done on the body is 0 Joules.

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