When a force of 1N acts on a body of mass 1 gram, the body receives an acceleration of

Options

A. `1 ms^(-2)`
B. `9.8 ms^(-2)`
C. `980 ms^(-2)`
D. `1000 ms^(-2)`

Explanation

To find the acceleration of a body when a force acts on it, we can use Newton's second law of motion, which states that:

\[ F = m \cdot a \]

Where:
- \( F \) is the force applied,
- \( m \) is the mass of the body,
- \( a \) is the acceleration produced.

### Step-by-Step Solution:

**Step 1: Identify the given values.**
- Force \( F = 1 \, \text{N} \)
- Mass \( m = 1 \, \text{g} \)

**Step 2: Convert the mass from grams to kilograms.**
Since the SI unit of mass is kilograms, we need to convert grams to kilograms:
\[ 1 \, \text{g} = 1 \times 10^{-3} \, \text{kg} \]

**Step 3: Use the formula for acceleration.**
Rearranging Newton's second law to solve for acceleration \( a \):
\[ a = \frac{F}{m} \]

**Step 4: Substitute the values into the formula.**
Now, substitute \( F = 1 \, \text{N} \) and \( m = 1 \times 10^{-3} \, \text{kg} \) into the equation:
\[ a = \frac{1 \, \text{N}}{1 \times 10^{-3} \, \text{kg}} \]

**Step 5: Calculate the acceleration.**
Since \( 1 \, \text{N} = 1 \, \text{kg} \cdot \text{m/s}^2 \), we can rewrite the equation as:
\[ a = \frac{1 \, \text{kg} \cdot \text{m/s}^2}{1 \times 10^{-3} \, \text{kg}} \]

Now, the kilograms cancel out:
\[ a = \frac{1}{1 \times 10^{-3}} \, \text{m/s}^2 \]
\[ a = 1000 \, \text{m/s}^2 \]

### Final Answer:
The acceleration of the body is \( 1000 \, \text{m/s}^2 \).

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