`7^( N^( 15))` and `8^(O^(16))` are a pair of

Options

A. isotopes
B. isobars
C. isotones
D. None of these

Answer

To determine the relationship between the pairs \(7^{(N^{15})}\) and \(8^{(O^{16})}\), we need to analyze the atomic structure of these elements, specifically focusing on their atomic numbers and mass numbers.

### Step-by-Step Solution:

1. **Identify the Elements**:
- The notation \(7^{(N^{15})}\) indicates that we have nitrogen (N) with an atomic number of 7 and a mass number of 15.
- The notation \(8^{(O^{16})}\) indicates that we have oxygen (O) with an atomic number of 8 and a mass number of 16.

2. **Define Atomic Number and Mass Number**:
- The atomic number (Z) is the number of protons in the nucleus of an atom.
- The mass number (A) is the total number of protons and neutrons in the nucleus.

3. **Calculate Neutrons**:
- For nitrogen \(N^{15}\):
- Atomic number (Z) = 7 (number of protons)
- Mass number (A) = 15
- Number of neutrons (N) = Mass number - Atomic number = \(15 - 7 = 8\)
- For oxygen \(O^{16}\):
- Atomic number (Z) = 8 (number of protons)
- Mass number (A) = 16
- Number of neutrons (N) = Mass number - Atomic number = \(16 - 8 = 8\)

4. **Compare Neutrons**:
- Both nitrogen \(N^{15}\) and oxygen \(O^{16}\) have the same number of neutrons, which is 8.

5. **Determine the Type of Pair**:
- Since both elements have the same number of neutrons but different atomic numbers and mass numbers, they are classified as **isotones**.

### Conclusion:
The pair \(7^{(N^{15})}\) and \(8^{(O^{16})}\) are isotones.

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