`alpha` particle is emitted by `92^(X^(238))` during radioactivity. The new specie Y should be:

Options

A. `90^(Y^(234))`
B. `90^(Y^(238))`
C. `92^(Y^(234))`
D. `94^(Y^(234))`

Answer

To find the new species Y after the emission of an alpha particle from the radioactive isotope \( ^{238}_{92}X \), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Composition of the Alpha Particle:**
An alpha particle is composed of 2 protons and 2 neutrons. It can be represented as \( ^{4}_{2}\text{He} \) or simply as \( \alpha \).

2. **Understand the Initial Isotope:**
The given isotope is \( ^{238}_{92}X \), where:
- The mass number (A) is 238.
- The atomic number (Z) is 92.

3. **Determine the Changes After Alpha Emission:**
When an alpha particle is emitted:
- The mass number of the new species (Y) will decrease by 4 (due to the 4 from the alpha particle).
- The atomic number of the new species (Y) will decrease by 2 (due to the 2 protons in the alpha particle).

4. **Calculate the New Mass Number:**
\[ \text{New mass number} = 238 - 4 = 234 \]

5. **Calculate the New Atomic Number:**
\[ \text{New atomic number} = 92 - 2 = 90 \]

6. **Write the New Species:**
The new species Y can be represented as \( ^{234}_{90}Y \).

### Final Answer:
The new species Y after the emission of the alpha particle is \( ^{234}_{90}Y \).

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