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In the balanced reaction aFe(2)O(3) + ...

In the balanced reaction
`aFe_(2)O_(3) + bH_(2) to cFe + dH_(2)O`
a, b, c and d, respectivel, are

A

1123

B

1111

C

1323

D

1223

Text Solution

AI Generated Solution

The correct Answer is:
To balance the reaction \( aFe_{2}O_{3} + bH_{2} \rightarrow cFe + dH_{2}O \), we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's break this down step by step: ### Step 1: Write the unbalanced equation The unbalanced equation is: \[ Fe_{2}O_{3} + H_{2} \rightarrow Fe + H_{2}O \] ### Step 2: Count the number of atoms of each element - On the left side (reactants): - Iron (Fe): 2 (from \( Fe_{2}O_{3} \)) - Oxygen (O): 3 (from \( Fe_{2}O_{3} \)) - Hydrogen (H): 2 (from \( H_{2} \)) - On the right side (products): - Iron (Fe): 1 (from \( Fe \)) - Oxygen (O): 1 (from \( H_{2}O \)) - Hydrogen (H): 2 (from \( H_{2}O \)) ### Step 3: Balance the iron (Fe) atoms To balance the iron atoms, we need 2 iron atoms on the product side. Therefore, we will put a coefficient of 2 in front of \( Fe \): \[ Fe_{2}O_{3} + H_{2} \rightarrow 2Fe + H_{2}O \] ### Step 4: Count the atoms again Now, let's recount: - On the left side: - Fe: 2 - O: 3 - H: 2 - On the right side: - Fe: 2 - O: 1 (from \( H_{2}O \)) - H: 2 (from \( H_{2}O \)) ### Step 5: Balance the oxygen (O) atoms We have 3 oxygen atoms on the left and only 1 on the right. To balance the oxygen, we need to put a coefficient of 3 in front of \( H_{2}O \): \[ Fe_{2}O_{3} + H_{2} \rightarrow 2Fe + 3H_{2}O \] ### Step 6: Count the hydrogen (H) atoms Now we recount: - On the left side: - Fe: 2 - O: 3 - H: 2 - On the right side: - Fe: 2 - O: 3 (from \( 3H_{2}O \)) - H: 6 (from \( 3H_{2}O \)) ### Step 7: Balance the hydrogen (H) atoms We have 6 hydrogen atoms on the right side but only 2 on the left. To balance the hydrogen, we need to put a coefficient of 3 in front of \( H_{2} \): \[ Fe_{2}O_{3} + 3H_{2} \rightarrow 2Fe + 3H_{2}O \] ### Final Step: Write the balanced equation The balanced equation is: \[ 1Fe_{2}O_{3} + 3H_{2} \rightarrow 2Fe + 3H_{2}O \] ### Coefficients: - \( a = 1 \) - \( b = 3 \) - \( c = 2 \) - \( d = 3 \) ### Summary of Coefficients: - \( a = 1 \) - \( b = 3 \) - \( c = 2 \) - \( d = 3 \)

To balance the reaction \( aFe_{2}O_{3} + bH_{2} \rightarrow cFe + dH_{2}O \), we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's break this down step by step: ### Step 1: Write the unbalanced equation The unbalanced equation is: \[ Fe_{2}O_{3} + H_{2} \rightarrow Fe + H_{2}O \] ### Step 2: Count the number of atoms of each element - On the left side (reactants): ...
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