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If a = 2 and b = 5, the value of the ex...

If a = 2 and b = 5, the value of the expression 2a-[3a+{4b-(2a-b)+5a}-7b] is :

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To solve the expression \( 2a - [3a + \{ 4b - (2a - b) + 5a \} - 7b] \) given \( a = 2 \) and \( b = 5 \), we will follow these steps: ### Step 1: Substitute the values of \( a \) and \( b \) Substituting \( a = 2 \) and \( b = 5 \) into the expression: \[ 2(2) - [3(2) + \{ 4(5) - (2(2) - 5) + 5(2) \} - 7(5)] \] ### Step 2: Calculate the values inside the brackets Calculating the values step by step: 1. Calculate \( 2(2) \): \[ 2(2) = 4 \] 2. Calculate \( 3(2) \): \[ 3(2) = 6 \] 3. Calculate \( 4(5) \): \[ 4(5) = 20 \] 4. Calculate \( 7(5) \): \[ 7(5) = 35 \] Now, substitute these values back into the expression: \[ 4 - [6 + \{ 20 - (4 - 5) + 10 \} - 35] \] ### Step 3: Solve the innermost bracket Now, solve the innermost bracket \( (4 - 5) \): \[ 4 - 5 = -1 \] So, we have: \[ 4 - [6 + \{ 20 - (-1) + 10 \} - 35] \] ### Step 4: Simplify the curly bracket Now, simplify the curly bracket: \[ 20 - (-1) = 20 + 1 = 21 \] So, we have: \[ 4 - [6 + \{ 21 + 10 \} - 35] \] Now, simplify \( 21 + 10 \): \[ 21 + 10 = 31 \] Now substitute back: \[ 4 - [6 + 31 - 35] \] ### Step 5: Simplify the square bracket Now, simplify the square bracket: \[ 6 + 31 = 37 \] \[ 37 - 35 = 2 \] So, we have: \[ 4 - [2] \] ### Step 6: Final calculation Now, perform the final calculation: \[ 4 - 2 = 2 \] Thus, the value of the expression is: \[ \boxed{2} \]
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MCGROW HILL PUBLICATION-FUNDAMENTALS OF ALGEBRA-Multiple Choice Questions
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