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What is the value of (tan (90^@-theta) s...

What is the value of `(tan (90^@-theta) sec (180^@-theta)sin(-theta))/(sin (180^@+theta) cot (360^@-theta) "cosec"(90^@-theta))` ?

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To solve the expression \[ \frac{\tan(90^\circ - \theta) \cdot \sec(180^\circ - \theta) \cdot \sin(-\theta)}{\sin(180^\circ + \theta) \cdot \cot(360^\circ - \theta) \cdot \csc(90^\circ - \theta)} \] we will simplify each trigonometric function step by step. ### Step 1: Simplify \(\tan(90^\circ - \theta)\) Using the co-function identity, we know that: \[ \tan(90^\circ - \theta) = \cot(\theta) \] ### Step 2: Simplify \(\sec(180^\circ - \theta)\) Using the identity for secant in the second quadrant: \[ \sec(180^\circ - \theta) = -\sec(\theta) \] ### Step 3: Simplify \(\sin(-\theta)\) Using the odd function property of sine: \[ \sin(-\theta) = -\sin(\theta) \] ### Step 4: Simplify \(\sin(180^\circ + \theta)\) Using the sine function property in the third quadrant: \[ \sin(180^\circ + \theta) = -\sin(\theta) \] ### Step 5: Simplify \(\cot(360^\circ - \theta)\) Using the cotangent property in the fourth quadrant: \[ \cot(360^\circ - \theta) = \cot(\theta) \] ### Step 6: Simplify \(\csc(90^\circ - \theta)\) Using the co-function identity for cosecant: \[ \csc(90^\circ - \theta) = \sec(\theta) \] ### Step 7: Substitute the simplified values into the expression Now substituting all simplified values back into the original expression: \[ \frac{\cot(\theta) \cdot (-\sec(\theta)) \cdot (-\sin(\theta))}{(-\sin(\theta)) \cdot \cot(\theta) \cdot \sec(\theta)} \] ### Step 8: Simplify the expression The numerator becomes: \[ \cot(\theta) \cdot \sec(\theta) \cdot \sin(\theta) \] The denominator becomes: \[ \sin(\theta) \cdot \cot(\theta) \cdot \sec(\theta) \] Thus, the expression simplifies to: \[ \frac{\cot(\theta) \cdot \sec(\theta) \cdot \sin(\theta)}{\sin(\theta) \cdot \cot(\theta) \cdot \sec(\theta)} = 1 \] ### Final Answer The value of the expression is: \[ \boxed{1} \]
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MCGROW HILL PUBLICATION-TRIGONOMETRY-Multiple Choice Questions
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