In a single throw of a die, what is the probabilityy of getting a number greater than or equal to 4?

Options

A. `1/2`
B. `1/3`
C. `2/3`
D. `1/4`

Answer

To find the probability of getting a number greater than or equal to 4 in a single throw of a die, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Total Number of Outcomes**:
- A standard die has 6 faces, numbered from 1 to 6. Therefore, the total number of outcomes when throwing a die is 6.
- **Total Outcomes = {1, 2, 3, 4, 5, 6}**

2. **Identify the Favorable Outcomes**:
- We need to find the outcomes that are greater than or equal to 4. The numbers that satisfy this condition are 4, 5, and 6.
- **Favorable Outcomes = {4, 5, 6}**
- The number of favorable outcomes is 3.

3. **Calculate the Probability**:
- Probability is calculated using the formula:
\[ \text{Probability} = \frac{\text{Number of Favorable Outcomes}}{\text{Total Number of Outcomes}} \]
- Substituting the values we found:
\[ \text{Probability} = \frac{3}{6} \]

4. **Simplify the Probability**:
- Simplifying \(\frac{3}{6}\) gives us:
\[ \frac{3}{6} = \frac{1}{2} \]

5. **Conclusion**:
- Therefore, the probability of getting a number greater than or equal to 4 in a single throw of a die is \(\frac{1}{2}\).

### Final Answer:
The probability of getting a number greater than or equal to 4 is \(\frac{1}{2}\).

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