[" Que."47:" If "x=t^(2)" and "y=2t],[" ,then equation of the normal at "t=1" is "]

Consider the parametric forms x=(t)+(1/t) and y=(t)-(1/t) of a curve Find the equation of the normal at t=2.

Find the equation of normal to the curves x=t^2, y=2t+1 at point

Find the equation of normal to the curves x=t^(2),y=2t+1 at point

Show that the locus represented by x = 1/2 a (t + 1/t) , y = 1/2 a (t - 1/t) is a rectangular hyperbola. Show also that equation to the normal at the point 't' is x/(t^(2) + 1) + y/(t^(2) - 1) = a/t .

Equation of normal to x= 2e^(t), y= e^(-t) " at " t=0 is

The equation of the normal to the parabola y^(2)=8x at the point t is

Find the equation of the tangents and normal to the curve x= sin 3t, y= cos 2t " at " t=(pi)/(4)

Find the equations of the tangent and normal to the curve x = a sin 3t, y = cos 2 t " at " t = (pi)/(4)

The equation of the normal at the point 't' to the curve x=at^(2), y=2at is :

Statement 1: The line a x+b y+c=0 is a normal to the parabola y^2=4a xdot Then the equation of the tangent at the foot of this normal is y=(b/a)x+((a^2)/b)dot Statement 2: The equation of normal at any point P(a t^2,2a t) to the parabola y^2 = 4a x is y=-t x+2a t+a t^3