[" The fourth,seventh and tenth terms of a "],[" G.P are "p,q,r" respectively then "],[qquad [p^(2)=q^(2)+r^(3)],[q^(2)=pr]],[p^(2)=qr],[pqr+pq+1=0]

If 3rd, 8th and 13th terms of a G.P are p ,q and r respectively, then which one of the following is correct? (i) q^(2)=pr (ii) r^(2)=pq (iii) pqr=1 (iv) 2q=p+r

Factorise: p^(2)q-pr^(2)-pq+r^(2)

If p,q,r are in A.P the p^(2)(q+r),q^(2)(r+p),r^(2)(p+q) are in

The sum of first p.q.r terms of an AP are a;b;c respectively.Show that a(q-r)/(p)+b(r-p)/(q)+c(p-q)/(r)=0

If p, q, r are in A.P the p^(2) (q + r), q^(2) (r + p), r^(2) (p+q) are in

If the pth,qth,and rth terms of an A.P.are in G.P.then the common ratio of the G.P.is a.(pr)/(q^(2)) b.(r)/(p) c.(q+r)/(p+q) d.(q-r)/(p-q)

If p = 4, q= 3 and r = -2, find the values of : (p^(2)+q^(2)-r^(2))/(pq+qr-pr)

If p, q, r be real then the intervals in which, f(x)=|(x+q^(2),pq,pr),(pq,x+p^(2),qr),(pr,qr,x+r^(2))|