[" Five numbers are selected from "1,2,3,4,5,6,7,8" and "9." The probability that their product is "],[" divisible by "5" or "7" is "]

A five digit number (having all different digits) is formed using the digits 1,2,3,4,5,6,7,8 and 9. The probability that the formed number either begins or ends with an odd digit,is equal to

In how many ways 5 distinct numbers can be selected from the natural numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 such that their product is even

Seven digits from the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9 are written in random order. Find the probability that the seven digited number is divisible by 9.

A 9 digit number using the digits 1,2,3,4,5,6,7,8&9 is written randomly without repetition.The probability that the number will be divisible by 9 is:

Five digited numbers are formed using {0,2,4,5,7} without repetetion. One number is selected at random. The probability that it is divisible by 5 is

The digits 1,2,3,4,5,6,7,8 and 9 are written in random order to form a nine digit number. The probability that this number is divisible by 4, is

The digits 1,2,3,4,5,6,7,8 and 9 are written in random order to form a nine digit number. The probability that this number is divisible by 4, is

Five different digits from the set of numbers {1, 2, 3, 4, 5, 6, 7} are written in random order. Find the probability that five-digit number thus formed is divisible by 9.