A cell of e.m.f. of 1.08 V is balanced by a 216 cm length of a potentiometer. What is the length of the wire that would balance a cell of e.m.f. 1.5 V ?

Obtain an expression for e.m.f. induced in a coil rotating with uniform angular velocity in a uniform magnetic field. Show graphically the variation of e.m.f. with time (t). Rewsistance of a potentiometer witre is 0*1" "Omega//cm . A cell of e.m.f. 1*5 V is balanced at 300 cm on this potentiometer wire, Calculate teh current and balancing length for another cell of e.m.f. 1*4 V on the same potentiometer wire.

A cell of e.m.f. 1 V gives a balance point at 40 cm length of a potentioeter wire. For another cell, the balance point shifts to 60 cm. Find the e.m.f. of the second cell.

Resistance of potentiometer wire is 0.1Omega//cm . A cell of emf 1.5V is balanced at 300cm on this potentiometer wire. Calculate the current and balancing length for another cell of emf 1.4V on the same potentiometer wire.

A cell of e.m.f. 1.2 V is balanced by 150 cm of potentiometer wire. When the cell is shunted by a resistance of 4 Omega , the balancing length is reduced by 30 cm. What is the internal resistance of the cell ?

A 10 wire potentiometer has first five wires of cross sectional radius r and next five wires of radius 2r . The wires are uniform and made of same material. An ideal cell of emf 2 V is connected across the potentiometer wire. What length of the potentiometer wire will balance the emf of– (a) a Daniell cell (emf = 1.0 V) (b) a Lechlanche cell (emf = 1.5 V) (c) a cell of emf 1.8 V ? Length of each wire is 100 cm.