The torque acting is 2000 Nm with an angular acceleration of `2rad//s^(2)` . The moment of inertia of body is

A torque of magnitude 2000 Nm acting on a body produces an angular acceleration of 20" rad/s"^(2) , The moment of inertia of the body is

If a torque of magnitude 100 Nm acting on a rigid body produces an angular acceleration of 2 rad//s^(2) , then the moment of inertia of that body will be

A torque of magnitude 400 N.m, acting on a body of mass 40 kg, Produces an angular acceleration of 20 rad/ s^(2) . Calculate the moment of inertia and radius of gyration of the body.

A torque of 400 Nm acting on a body of mass 40 kg produces an angular acceleration of 20 rad/s^2 . Calculate the moment of inertia and radius of gyration of the body.

The torque needed to produce an angular acceleration of 18rad/ "sec"^2 in a body of moment of inertia 2.5kg- m^2 would be -

A constant torque of 31.4 Nm is applied to a pivoted wheel. If the angular acceleration of the wheel is 2pi" rad/s"^(2) , then its moment of inertia is

A torque of 2.0xx10^(-4)Nm is applied to produce an angular acceleration of 4"rad"s^(-2) in a rotating body. What is the moment of inertia of the body?

A torque of 2.0 xx 10^(-4) Nm is applied to produce an angular acceleration of 4 "rad s"^(-2) in a rotating body. What is the moment of inertia of the body ?