एक अभिक्रिया `2A+BtoAB_2` जिसका वेग नियम वेग `=K[A]^(2)` है का वेग नियतांक `0.50 mol^(-1)Ls^(-1)` है। इस अभिक्रिया के वेग की गणना कीजिए यदि `[A]=0.60 mol L^(-1)[B]=0.50 mol L^(-1) ` है।

The rate of a reaction 2A+B rarr A_2B . has rate law : rate = k [A]^2 with the rate constant equal to 0.50 mol^(-1)" L sec"^(-1) . Calculate the rate of reaction when (i) [A] = 0.60 mol L^(-1) , [B] =-0.05 mol L^(-1) and (ii) When concentration of A and B have been reduced to 1/4 th

For the reaction, 2A + B to A_(2)B , the reaction rate = k[A][B]^(2) with k = 2.0 xx 10^(-6) mol^(-2) L^(2)s^(-1) . Calculate the initial rate of the reaction when [A] = 0.1 mol L^(-1) , [B]= 0.2 mol L^(-1) . Also calculate the reaction rate when [a] is reduced to 0.06 mol L^(-1) .

The rate law expression of a reaction 2A+B rarr A_(2)B is rate = k[A]^(2) with rate constant k =0.65 mol^(-1) L s^(-1) calculate rate of reaction when (a) [A]=0.25 mol L^(-1) [B]=1.84 mol L^(-1)