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The equation of the circle whose centre ...

The equation of the circle whose centre lies in the first quadrant and which touches the coordinate axes and the line `(x//3)+(y//4)=1" is "x^(2)+y^(2)-2cx-2cy+c^(2)=0` then c=

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The equation of the circle which touches the axes of coordinates and the line (x)/(3)+(y)/(4)=1 and whose center lies in the first quadrant is x^(2)+y^(2)-2cx-2cy+c^(2)=0, where c is (a) 1( b) 2 (c) 3 (d) 6

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