The rate constant of a reaction increases by 5% when its temperature is raised from `27^@c` to `28^@c.` The activation energy of the reaction is

The rate constant of a reaction is doubled when the temperature is raised from 298 K to 308 K. Calculate the activation energy.

The specific rate constant for a reaction increases by a factor if the temperature is changed from 27^(@) C to 47^(@) C. Find the activation energy for the reaction. (R = 198 cal )

The specific rate constant of a particular reaction quadruples when temperature is changed from 27^@" to "47^@C . Find activation energy for the reaction.

The specific rate constant of a particular reaction quadruples when temperature is changed from 27^@" to "47^@C . Find activation energy for the reaction.

The rate constant of a reaction increases by five times on increase in temperature from 27^@C to 52^@C . The value of activation energy in kJ "mol"^(-1) is ______ (Rounded-off to the nearest integer)

If the rate of a reaction gets doubled as the temperature is increased from 27^@ " to " 37^@C . Find the activation energy of reaction?

If the rate of a reaction gets doubled as the temperature is increased from 27^@ " to " 37^@C . Find the activation energy of reaction?