यदि रेखा 3x+3y+7=0 को `x cos alpha + y sin alpha =p` परिवर्तित करें, तो p का मान होगा

यदि x^(2)+2=0 हो तो x का मान होगा-

If the equation 3x + 3y + 5 = 0 is written in the form x cos alpha + y sin alpha = p , then the value of sin alpha + cos alpha is

If the equation 3x + 3y + 5=0 is written in the form x cos alpha + y sin alpha = p , then the value of sin alpha + cos alpha is a) sqrt2 b) (1)/( sqrt2) c) - sqrt2 d) - (1)/( sqrt2)

If we reduce 3x+3y+7=0 to the form x cos alpha+y sin alpha=p, then find the value of p

If we reduce 3x+3y+7=0 to the form x cos alpha+y sin alpha=p, then the value of p is (7)/(2sqrt(3))( b) (7)/(3)( c) (3sqrt(7))/(2)( d) (7)/(3sqrt(2))

If cos x.cos y + sin x.sin y = -1 then cos x + cos y is यदि cos x.cos y + sin x.sin y = -1 हो, तो cos x + cos y का मान क्या होगा?

If cos x + cos y + cos alpha = 0 and sin x + sin y + sin alpha = 0 then cot ((x + y) / (2)) =

If line x cos alpha + y sin alpha = p " touches circle " x^(2) + y^(2) =2ax then p =

If x sin ^ (3) alpha + y cos ^ (3) alpha = sin alpha cos alpha and x sin alpha-y cos alpha = 0 then x ^ (2) + y ^ (2) =