The following travelling electromagnetic wave `E_(x) = 0, E_(y) = E_(0)sin(kx + omegat), E_(z) = –2E_(0)sin(kx + omegat)` is-

A electromagnetic wave going through a medium is given by E = E_(0)sin (kx – omegat) and B = B_(0) sin (kx – omegat) then

An electromagnetic wave going through vacuum is described by E= E_0 sin(kx- omega t), B=B_0sin(kx-omega t) . Then

An electromagnetic wave going through vacuum is described by E= E_0 sin(kx- omega t), B=B_0sin(kx-omega t) . Then

An em wave going through vacuum is described by E=E_0sin(kx-omegat) B=B_0sin(kx-omegat)

The electric field of an electromagnetic wave travelling through vacuum is given by the equation E = E_(0) "sin"(kx - omegat) The quantity that is independent of wavelength is

The electric field of an electromagnetic wave travelling through vaccum is given by the equation E = E_(0) "sin"(kx - omegat) The quantity that is independent of wavelength is