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Find the equation of the line through the point of intersection of the lines `3x-4y+1=0` and `5x+y-1=0` and perpendicular to the line `2x-3y=10`

Answer

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Find the equation of the line passing through the point of intersection of the lines x+2y-5=0 and 3x+7y-17=0 and is perpendicular to the line 3x+4y-10=0

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Knowledge Check

  • Find the equation of the line which passes through the point of intersection of the lines 2x-y+5=0 and 5x+3y-4 =0 and is perpendicular to the line x-3y+21 =0

    A
    2x+y +8 =0
    B
    3x+4y -7=0
    C
    3x+y=0
    D
    none of these
  • The equation of the line passing through the point of intersection of the lines x-3y+2=0 and 2x+5y-7=0 and perpendicular to the line 3x+2y+5=0 is

    A
    `2x-3y+1=0`
    B
    `6x-9y+11=0`
    C
    `2x-3y-5=0`
    D
    `3x+2y+1=0`
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    Find the equation of a line passing through the point of intersection of the lines 3x+5y=-2 and 5x-2y=7 and perpendicular to the line 4x-5y+1=0 .

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