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" (ii) "(1+i^(3))(1+(1)/(i))^(2)(i^(4)+(...

" (ii) "(1+i^(3))(1+(1)/(i))^(2)(i^(4)+(1)/(i^(4)))

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Simplify : (1+i^(3))(1+(1)/(i))^(2)(i^(4)+(1)/(i^(4)))

Simplify: (1)/(i) + (1)/(i^(2)) + (1)/(i^(3)) + (1)/(i^(4))

Simplify: (1)/(i)- (1)/(i^(2)) + (1)/(i^(3)) - (1)/(i^(4))

Prove that: (i) (1-i)^(2)=-2i (ii) (1+i)^(4)xx(1+(1)/(i))^(4)=16 (iii) {i^(19)+((1)/(i))^(25)}^(2)=-4 (iv) i^(4n)+i^(4n+1)+i^(4n+2)+i^(4n+3)=0 (v) 2i^(2)+6i^(3)+3i^(16)-6i^(19)+4i^(25)=1+4i .

Simplify the following : (i) [i^(19) +(1)/(i^(25))]^(2) (ii) [i^(5)- (1)/(i^(3))]^(4)

Simplify the following : (i) [i^(19) +(1)/(i^(25))]^(2) (ii) [i^(5)- (1)/(i^(3))]^(4)

((1+i)/(1-i))^(4)+((1-i)/(1+i))^(4)=

find the value of (1)/(i)+(1)/(i^(2))+(1)/(i^(3))+(1)/(i^(4))

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)