cot^(2)A((sec A-1)/(1+sin A))+sec^(2)A((sin A-1)/(1+sec A))=0

(cot^(2)A(sec A-1))/(1+sin A)=sec^(2)A((1-sin A)/(1+sec A))

((sin 2A)/(sec A -1))((sec 2A)/(sec 2A+1))=

The value of (cot^(2)alpha)((sec alpha-1)/(1+sin alpha))+sec^(2)alpha((sin alpha-1)/(1+sec alpha)) is

cot^(2) theta ((sec theta -1)/(1+ sin theta ))+ sec^(2) theta ((sin theta -1)/( 1+ sec theta )) =

(1+sec A)/(sec A)=(sin^(2)A)/(1-cos A)

((sin2A)/(secA-1))((sec2A)/(sec2A+1))=

Prove the following identity : cot^2 theta ((sec theta-1)/(1+sin theta))+ sec^2 theta ((sin theta-1)/(1+sec theta)) =0 .

((sin2A)/(sec A-1))((sec2A)/(sec2A+1))=

The trigonometric expression: cot^(2)[(sec theta-1)/(1+sin theta)]+sec^(2)theta[(sin theta-1)/(1+sec theta)] has the value has the

What will be the value of following identities : (cot^(2) theta (sec theta -1))/((1+ sin theta))+ (sec^(2)theta (sintheta -1))/((1+ sec theta))