A radioactive decay can form an isotope of the original nucleus with the emission of particles

A radioactive decay can form as isotope of the original nucleus with the emission of particles

Originally the radioactive beta decay was thought as a decay of a nucleus with the emission of electrons only (Case I). However, in addition to the electron, another (nearly) massless and electrically neutral particle is also emitted (Case II). Based on the figure below, which of the following is correct:

In a radioactive decay, a nucleus is transformed into another with the emission of a positron. In this process the neutron-proton ratio

In a radioactive decay, a nucleus is transformed into another with the emission of a positron. In this process the neutron-proton ratio

Which one of the following combinations of radioactive decay results in the formation of an isotope of the original nucleus?

When a radioactive isotope _88Ra^228 decays in series by the emission of 3 alpha particles and a beta particle, the isotope finally formed is

Which one of the following combinations of radioactive decay results in the formation of an isotope of original nucleus ?

When a radio active isotopes "_88Ra^228 decays in series by the emission of three alpha -particles and a beta -particle, the isotopes finally formed is ...

U^238 decays into Th^234 by the emission of an a-particle. There follows a chain of further radioactive decays, either by alpha -decay or by beta- decay. Eventually a stable nuclide is reached and after that, no further radioactive decay is possible. which of the following stable nuclides is the end product of the U^238 radioactive decay chain ?