A `10 gram` sample of natural gas containing `CH_(4)` and `C_(2)H_(4)` was burnt in excess of oxygen to give `29.0 "grams"` of `CO_(2)` and some water. How many games of water are formed :

A 10 gram sample of natural gas containing CH_(4) and C_(2)H_(4) was burnt in excess of oxygen to give 29.0 "grams" of CO_(2) and some water. How many grams of water are formed :

A 5.0g sample of a natural gas consisting of CH_(4),C_(2)H_(4) was burnt in excess of oxygen yielding 14.5g CO_(2) and some H_(2)O as product. What is weight percentage of CH_(4) and C_(2)H_(4) in mixture?

A 5.00 gm sample of a natural gas, consisting of methane CH_(4) , and ethylene, C_(2)H_(4) was burnt in excess oxygen , yeilding 44/3 gm of CO_(2) and H_(2)O as products . What mole percent of the sample was ethylene ?

280 g of a mixture containing CH_(4) and C_(2)H_(6) in 5:2 molar ratio is burnt in presence of excess of oxygen. Calculate total moles of CO_(2) produced.

280 g of a mixture containing CH_(4) and C_(2)H_(6) in 5:2 molar ratio is burnt in presence of excess of oxygen. Calculate total moles of CO_(2) produced.

4g of hydrogen is burnt with 4g of oxygen. How many grams of water can be formed?