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When a gas is bubbled through water at 298 K, a very dilute solution of gas is obtained . Henry's law constant for the gas is 100 kbar. If gas exerts a pressure of 1 bar, the number of moles of gas dissolved in 1 litre of water is

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When a gas is bubbled through water at 298 K, a very dilute solution of the gas is obtained. Henry's law constant for the gas at 298 K is 100kbar. If the gas exerts a partial pressure of 1 bar, the number of millimoles of the gas dissolved in one litre of water is

When a gas is bubbled through water at 298K, a very dilute solution of the gas is obtained. Henry's law constant for the gas at 298K is 100 kbar. If the gas exerts a partial pressure of 1 bar. The number of millimoles of the gas dissolved in one litre of water is

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Let gas (A) present in air is dissolved in 20 moles of water at 298K and 20 atm pressure. The mole fraction of gas (A) in air is 0.2 and the Henry's law constant for solubility of gas (A) in water at 298K is 1×10^5atm.The number of mole of gas (A) dissolved in water will be

Let gas (A) present in air is dissolved in 20 moles of water at 298K and 20 atm pressure. The mole fraction of gas (A) in air is 0.2 and the Henry's law constant for solubility of gas (A) in water at 298K is 1×10^5 atm.The number of mole of gas (A) dissolved in water will be

The Henry’s law constant of a gas is 6.7×10^-4 mol/(L bar). Its solubility when the partial pressure of the gas at 298K is 0.65 bar is

If N_2 gas is bubbled through the water is 293K, how many millimoles of N_2 gas would dissolve in 1 litre of water. Assume that N_2 exerts a partial pressure of 0.987 bar. The K_H for N_2 at 293K is 76.48 K bar.

CO_(2) gas is bubbled through water during a soft drink manufacturing process at 298 K. If CO_(2) exerts a partial pressure of 0.835 bar then x m mol of CO_(2) would dissolve in 0.9 L of water. The value of x is ________ . (Nearest integer) (Henry's law constant for CO_(2) at 298 K is 1 . 67 xx 10^(3) bar )