A beam of light is converging towards a point. A plane parallel plate of glass of thickness t, refractive index  is introduced in the path of the beam. The convergent point is shifted by (assume near normal incidence) :

A beam of light is converging towards a point. A plane parallel plate of glass of thickness t, refractive index mu is introduced in the path of the beam. The convergent point is shifted by (assume near normal incidence) :

A beam of light is converging towards a point P on a screen. A plane parallel plate of glass of thickness in the direction of beam = t , refractive index = n is introduced in the path of the beam. The convergence point is shifted by

A beam of light is converging towards a point I on a screen. A plane glass plate whose thickness in the direction of the beam =t , refractive index =mu , is introduced in the path of the beam. The convergence point is shifted by

A beam of light is converging towards a point I on a screen. A plane glass plate whose thickness in the direction of the beam =t , refractive index =mu , is introduced in the path of the beam. The convergence point is shifted by A. t(1-1/(mu)) away B. t(1+1/(mu)) away C. t(1-1/(mu)) nearer D. t(1+1/(mu)) nearer

A beam of light is converging towards a certain point. A parallel sided glass plate is introduced in the path of the converging beam. How will the point of convergence be shifted ?

A beam of light is converging towards a point on a screen.A plane parallel plate of glass is introduced in the path of this converging beam.How will the point of convergence be shited ?Draw the ray diagram.

When a transparent parallel plate of uniform thickness t and refractive index mu is interposed normally in the path of a beam of light, the optical path is

When a transparent parallel plate of uniform thickness t and refractive index mu is interposed normally in the path of a beam of light, the optical path is