Home
Class 11
MATHS
ABC is a variable triangle such that A ...

`ABC` is a variable triangle such that `A` is (1, 2), and B and C on the line `y=x+lambda(lambda` is a variable). Then the locus of the orthocentre of `DeltaA B C` is `x+y=0` (b) `x-y=0` `x^2+y^2=4` (d) `x+y=3`

Promotional Banner

Similar Questions

Explore conceptually related problems

ABC is a variable triangle such that A is (1,2), and B and C lie on the line y=x+lambda (lambda " is a variable ). Then the locus of the the orthocenter of " Detla ABC is

ABC is a variable triangle such that A is (1, 2), and B and C on the line y=x+lambda(lambda is a variable). Then the locus of the orthocentre of DeltaA B C is (a) x+y=0 (b) x-y=0 x^2+y^2=4 (d) x+y=3

ABC is a variable triangle such that A is (1, 2),and B and C on the line y=x+lambda(lambda is a variable).Then the locus of the orthocentre of Delta ABC is x+y=0 (b) x-y=0x^(2)+y^(2)=4( d )x+y=3

A B C is a variable triangle such that A is (1, 2), and Ba n dC on the line y=x+lambda(lambda is a variable). Then the locus of the orthocentre of "triangle"A B C is x+y=0 (b) x-y=0 x^2+y^2=4 (d) x+y=3

A B C is a variable triangle such that A is (1, 2), and Ba n dC on the line y=x+lambda(lambda is a variable). Then the locus of the orthocentre of "triangle"A B C is x+y=0 (b) x-y=0 x^2+y^2=4 (d) x+y=3

A B C is a variable triangle such that A is (1,2) and B and C lie on line y=x+lambda (where lambda is a variable). Then the locus of the orthocentre of triangle A B C is (a) (x-1)^2+y^2=4 (b) x+y=3 (c) 2x-y=0 (d) none of these

A B C is a variable triangle such that A is (1,2) and B and C lie on line y=x+lambda (where lambda is a variable). Then the locus of the orthocentre of triangle A B C is (a) (x-1)^2+y^2=4 (b) x+y=3 (c) 2x-y=0 (d) none of these

ABC is a variable triangle such that A is (1,2) and B and C lie on line y=x+lambda (where lambda is a variable).Then the locus of the orthocentre of triangle ABC is (a)(x-1)^(2)+y^(2)=4(b)x+y=3( c) 2x-y=0 (d) none of these

If points A and B are (1, 0) and (0, 1), respectively, and point C is on the circle x^2+y^2=1 , then the locus of the orthocentre of triangle A B C is (a) x^2+y^2=4 (b) x^2+y^2-x-y=0 (c) x^2+y^2-2x-2y+1=0 (d) x^2+y^2+2x-2y+1=0

If points Aa n dB are (1, 0) and (0, 1), respectively, and point C is on the circle x^2+y^2=1 , then the locus of the orthocentre of triangle A B C is (a) x^2+y^2=4 (b) x^2+y^2-x-y=0 (c) x^2+y^2-2x-2y+1=0 (d) x^2+y^2+2x-2y+1=0