A linear SHM is represented by `x=5sqrt(2) ("sin" 2pi t+ "cos" 2pi t)`cm.
What is the amplitude of SHM ?

A S.H.M. is represented by x= 5 sqrt2 (sin2pit+cos 2 pi t) amplitude of the S.H. M is

The SHM is represented by y= 3sin 314 t+ 4 cos 314t y in cm and t in second. Find the amplitude of SHO.

Two S.H.M. s are represented by the equation x_(1)=3"sin" (2pi t+(pi)/(4)) " and " x_(2)=3sqrt(2)["sin" (2pi t)+"cos"(2pi t)] What is the ratio of the amplitudes of x_(1) " and " x_(2) ?

A SHM is represented by y(t) =5 sin(20t+0.5) m where t is in S. What is amplitude and time period.

Equation of SHM for two particles is x_1 = 5 sin (wt + pi/4) and x_2 = 5 sqrt(2)[sin(2 pi t) + cos ( 2 pi t)] . Then how many times amplitude of second particle greater than first.

Two simple harmonic motions are represented by the equations : x_1 = 5 sin (2 pi t + pi//4 ) , x_2 = 5^(2) (sin2 pi t + cos2 pi t) What is the ratio of their amplitudes ?

The displacement of a particle in S.H.M. is given by x=5["cos" pi t + "sin" pi t] where x is in metre. The amplitude of motion of the particle is given by

The S.H.M.s of two particles are given by y_(1)=10 "sin" [2pi t +(pi)/(6)] " and " y_(2) =5["sin" 2pi t + sqrt(3) "cos" 2 pi t] The ratio of their amplitudes is

The S.H.M.s of two particles are given by y_(1)=10 "sin" [2pi t +(pi)/(6)] " and " y_(2) =5["sin" 2pi t + sqrt(3) "cos" 2 pi t] The ratio of their amplitudes is

An SHM is given by the equation x = 8 sin (4 pi t) + 6 cos (4pit)] cm find its amplitude and period