रेखा `(2x-3y+4)+k(x-2y+3)=0,k in R ` बिन्दु (2,3) के प्रतिबिम्ब का बिन्दुपथ (locus) है :

{:(2x - 3y = k),(4x + 5y = 3):}

{:(2x + 3y = 2),((k + 2)x + (2k + 1)y = 2(k - 1)):}

Locus of the image of the point ( 2 ,3) in the line ( 2x - 3y + 4 ) + k ( x - 2y + 3 ) = 0 , k in RR is a _

The value of k for which the graph of (k- 1)x+ y-2= 0 and (2-k)x-3y+ 1) =0 are parallel is k का मान जिसके लिए (k- 1)x+ y-2= 0 और (2-k)x-3y+ 1) =0 के ग्राफ समांतर हो, है-

The line 2x+3y=5 , 2x+y=k , 2x-y-1=0

Locus of the image of the point (2,3) in the line (2x-3y+4)+k(x-2y+3)=0, k in R is a

Locus of the image of the point (2,3) in the line (2x-3y+4)+k(x-2y+3)=0 , k in R, is a

Locus of image of the point (2,3) in the line (2x-3y+4)+k(x-2y+3)=0 ,k in R is

Locus of the image of the point (2,3) in the line (2x-3y+4)+k(x-2y+3)=0 , k inR , is a

If 3x - 4y + k = 0 is a tangent to x^(2) - 4y^(2) = 5 find the value of k.