The equation to the locus of points equidistant from the points ` ( 2 , 3 ) , ( - 2, 5 ) ` is

The equation to the locus of points equidistant from the points (-3, 4),(3, 4) is

The equation of the locus of the points equidistant from the points A(-2,3) & B(6,-5) is

A: The equation to the locus of points which are equidistant from the points ( - 3, 2 ) , (0, 4 ) is 6x + 4y - 3 =0 . R : The locus of points which are equidistant to A, B is perpendicular bisector of AB

If the equation of the locus of points equidistant from the points ( - 2, 3 ) , ( 6, -5 ) is a x + by + c = 0 then ascending order of a, b , c is

Find the equation to the locus of points equidistant from the points (a + b,a - b),(a - b,a + b)

Find the equation to the locus of points equidistant from the points (a + b,a - b),(a - b,a + b)

Find the equation to the locus of points equidistant from the points (-3,2),(0,4)

Find the equation to the locus of points equidistant from the points (-3,2),(0,4)

The equation of the locus of the points equidistant from the point A(-2,3) and B(6,-5) is

The equation of the locus of points which are equidistant from the points (2,-3) and (3,-2) is