The minimum quantity of `H_(2)`S needed to precipitate 64.5 g of `Cu^(2+)` will be nearly.

The minimum quantity in gram of H_(2)S needed to precipitate 63.5 g of Cu^(2+) will ne nearly

According to the following reaction the minimum quantity in gm of H_(2)S needed to precipitate 63.5gm of Cu^(2+) ions will be nearly: Cu^(2+) + H_(2)S rArr CuS + 2H^(+)