A radioactive element `._90 X^238` decay into `._83 Y^222`. The number of `beta-`particles emitted are.

A radioactive element "_90X^(238) decays into "_83Y^222 . Thenumber of beta -particle emitted are:

A radio active element "_90X^238 decays into "_83X^222 . The no. of B particles emitted are—

A radioactive element, U_92^238 undergoes successive radioactive decay and decays into Pb_82^206 The number of alpha and beta particles emitted respectively are

A radioactive element, U_92^238 undergoes successive radioactive decay and decays into Pb_82^206 The number of alpha and beta particles emitted respectively are

A radioactive reaction is _92U^238 rightarrow _82Pb^206 . Number of alpha and beta particles emitted are

A radioactive element ""_(92) X^(238) emits one alpha - particle and one beta ' particle in succession. What is the mass number of new element formed?

A radioactive substance disintegrate as follows: ""_(92)X^(234) rarr ""_(87)Y^(222) The number of alpha and beta particle emitted from this reaction is