The capacitance of a parallel plate capacitor is `C` when the region between the plate has air. This region is now filled with a dielectric slab of dielectric constant `k.` The capacitor is connected to a cell of `emfE`, and the slab is taken out

The capacitance of a parallel plate capacitor is C_(0) when the region between the plates has air. This region is now filled with a dielectric slab of dielectric constant K . The capacitor is connected to a cell of emf V and slab is taken out. Find (a) charge flown through the cell (b) energy absorbed by the cell and (c) change in energy stored in the capacitor.

The capacitance of a parallel -plate capacitor is C_(0) when the region between the plates has air. This region is now filled with a dielectric slab of dielectric constant K . The capacitor is connected to a cell of emf varepsilon and the slab is takenout

In a parallel-plate capacitor, the region between the plates is filled by a dielectric slab. The capacitor is connected to a cell and the slab is taken out. Then

In a parallel-plate capacitor, the region between the plates is filled by a dielectric slab. The capacitor is connected to a cell and the slab is taken out. Then

A parallel plate capacitor has a capacity 80xx10^(-6)F , when air is present between its plates. The space between the plates is filled with a dielectric slab of dielectric constant 20. The capacitor is now connected to a battery of 30V by wires. The dielectric slab is then removed. Then, the charge passing through the wire is

A parallel plate capacitor has a capacity 80 xx 10^(-6) F, when airs present between the plates. The volume between the plates is then completely filled with a dielectric slab of dielectric constant 20. The capacitor is now connected to a battery of 30 V by wires. The dielectric slab is then removed. Then, the charge that passes now through the wire is

In a parallel plate capacitor, the region between the plates is filled by a dielectric slab. The capacitor is charged from a cell and then disconnected from it. The slab is now taken out :

Space between the plates of a parallel plate capacitor is filled with a dielectric slab. The capacitor is charged and then the supply is disconnected to it. If the slab is now taken out then

A parallel-plate capacitor has plate area A , the distance between its two plates x and y is d and a dielectric slab of dielectric constant epsilon_(r) is filled between the regions. It is connected to a cell of emf E . If the dielectric slab is removed, then