If the normal to differentiable curve y = f(x) at x = 0 be given by the equation `3x-y + 3 = 0`, then the value of `lim_(x->0)` `x^2/(f(x^2)-5f(4x^2)+ 4f(7x^2))` is

If the normal to differentiable curve y=f(x) at x=0 be given by the equation 3x-y+3=0, then the value of lim_(x rarr0)(x^(2))/(f(x^(2))-5f(4x^(2))+4f(7x^(2))) is

If the normal to the curve y=f(x) at x=0 be given by the equation 3x-y+3=0 , then the value of lim_(x rarr0)x^(2){f(x^(2))-5f(4x^(2))+4f(7x^(2))}^(-1) is (-1)/(k) then k =

If the equation of the normal to the curve y=f(x) at x =0 is 3x-y+3=0 then the value of lim_(x rarr0)(x^(2))/({f(x^2)-5f(4x^(2))+4f(7x^(2))}) is

If the equation of the normal to the curve y=f(x) at x=0 is 3x-y+3=0 then the value of lim_(xrarr0) (x^(2))/({f(x^(2))-5f(4x^(2))+4f(7x^(2))}) is

If f''(0)=k,kne0 , then the value of lim_(xto0)(2f(x)-3f(2x)+f(4x))/(x^2) is

If f'(x)=k,k!=0, then the value of lim_(x rarr0)(2f(x)-3f(2x)+f(4x))/(x^(2)) is

If f''(0)=k,kne0 then the value of lim_(xrarr0)(2f(x)-3f(2x)+f(4x))/(x^(2)) is

If f'(0)=3 then lim_(x rarr0)(x^(2))/(f(x^(2))-6f(4x^(2))+5f(7x^(2))=)

Let f''(x) be continuous at x = 0 and f"(0) = 4 then value of lim_(x->0)(2f(x)-3f(2x)+f(4x))/(x^2)