The balancing length for a cell is 560cm in a potentiometer experiment . When an external resistance of 10 ohm are connected in parallel to the cell, the balancing length changes by 60cm. find the internal resistance of the cell in ohm , is

The balancing length for a cell is 560 cm in a potentiometer experiment. When an external resistance of 10 Omega is connected in parallel to the cell , the balancing length changes by 60 cm. If the internal resistance of the cell is (n)/(10) Omega the value of n is ....

In a potentiometer experiment the balancing length with a cell is 560 cm. When an external resistance of 10Omega is connected in parallel to the cell, the balancing length changes by 60 cm. Find the internal resistance of the cell.

In a potentiometer experiment the balancing length with a cell is 560 cm. When an external resistance of 10Omega is connected in parallel to the cell, the balancing length changes by 60 cm. Find the internal resistance of the cell.

In a potentiometer experiment, the balancing length with a cell is 560cm. When an external resistance of 10ohms is connected in parallel to the cell the balancing length changs by 60cm. The internal resistance of the cell in ohm is

In a potentiometer experiment the balancing length with a cell is 560 cm. When an external resistance of 10 Omega is connected in parallel to the cell, the balancing length changes to 60 cm. The internal resistance of the cell is

A battery of unknown emf connected to a potentiometer has balancing length 560 cm. If a resistor of resistance 10 ohm, is connected in parallel with the cell the balancing length change by 60 cm. If the internal resistance of the cell is n/10 ohm, the value of 'n' is