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Find the sum series: tan^-1 (1/3)+tan^-1...

Find the sum series: `tan^-1 (1/3)+tan^-1 (1/7)+tan^-1(1/13)+…to oo`

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Prove that : 2 tan^-1(1/7) + tan^-1(1/3) = tan^-1(9/13)

If "S" is the sum of the first "10" terms of the series tan "^(-1)((1)/(3))+tan^(-1)((1)/(7))+tan^(-1)((1)/(13))+tan^(-1)((1)/(21))+.... ,then "tan(S)" is equal to:

Prove that tan^-1(1/7)+tan^-1(1/13)=tan^-1(2/9)

Prove that tan^-1 (1/7) + tan^-1 (1/13) = tan^-1 (2/9)

PT tan^(-1)(3/4)+tan^(-1)(1/3)=tan^(-1)(13/9)