Graph between `log((x)/(m)) vs log P` is provided for adsorption of `NH_(3)` gas on metal surface. Calculate weight of `NH_(3)` gas (in gm) absorbed by 24 g of metal surface at 2 atm pressure. (Take `log2=0.3`)

Graph between log(x/m) vs logP has a slope=2 and intercept = 0.477. Find (x/m) at pressure 4 atm.

Graph between log(x/m) vs logP has a slope=2 and intercept = 0.477. Find (x/m) at pressure 4 atm.

For adsorption of gas on solid surface the plots of log x/m vs log P is linear with a slope equal to :

A plot of log (x/m) versus log p for the adsorption of a gas on the surface of a solid gives a straight line which slope equal to :

For a adsorption of gas on solid surface, the plots of log x/m vs. log P is linear with a slope equal to

Graph between log x/m and log P is a straight line at angle of 45^(@) with intercept 0.4771 on y-axis. Calculate the amount of gas adsorbed in gram per gram of adsorbent when pressure is 3 atm.

Graph between log x/m and log P is a straight line at angle of 45^(@) with intercept 0.4771 on y-axis. Calculate the amount of gas adsorbed in gram per gram of adsorbent when pressure is 3 atm.

A graph between (x/m) vs log p gives a straight lien with slope equal to 45^@ and interecept on the log (x/m) axis as 0.3. Calculate the amount of gas adsorbed per gram of charcoal at a pressure of 0.95 atm.

In an Adsorption experiment a graph between log x/m versus log P was found to be linear with a slope of 45^(@) the intercept of the log x/m was found to be 0.3010. Calculate the amount of gas adsorbed per gram of charcoal under a pressure of 0.6 bar.