`int_0^1 x^2 sin^(-1) x dx`

Evaluate: int_0^1sin^(-1)x\ dx

int_(0)^(1) sin^(-1) x dx =(pi)/(2) -1

int_(0)^(1) sin^(-1) x dx =(pi)/(2) -1

int_0^1 sin^-1 x dx=pi/2-1

int_0^1 sin^-1x dx=pi/2-1

int_0^(1)(sin^(- 1)x)/x dx=

show that (a) int_(0) ^(2pi) sin ^(3) x dx = 0 , (b) int_(-1)^(1) e^(-x^(2)) dx = 2 int_(0)^(1) e^(-x^(2)) dx

Find the value of int_0^1{(sin^(-1)x)//x}dx

Find the value of int_0^1{(sin^(-1)x)//x}dx