If line ` 2x - y + k = 0 ` is a diameter of circle
` x^(2) + y^(2) + 6x - 6y + 5 = 0 ` , then k =

If the line 2x-y + k = 0 is a diameter of the circle x^2 + y^2 + 6x - 6y + 5 = 0 , then k is:

The line x + 3y = 0 is a diameter of the circle x^(2) + y^(2) + 6x + 2y = 0 .

If the line x + 2by + 7 = 0 is a diameter of the circle x^(2) + y^(2) - 6x + 2y = 0 , then : b =

If the circle x^(2) + y^(2) + 6x - 2y + k = 0 bisects the circumference of the circle x^(2) + y^(2) +2x - 6y - 15 = 0 , then k =

If y = 2x + K is a diameter to the circle 2(x^(2) + y^(2)) + 3x + 4y –1 = 0 , then K equals

The line x+3y=0 is a diameter of the circle x^(2)+y^(2)+6x+2y=0

The line x+3y=0 is a diameter of the circle x^(2)+y^(2)-6x+2y=0

The length of diameter of the circle x^(2) + y^(2) + 4x - 7y - k = 0 is 9, find k.