If `(a,0)`, agt 0, is the point where the curve `y=sin 2x-sqrt3 sin x` cuts the x-axis first, A is the area bounded by this part of the curve, the origin and the positive x-axis. Then

Area bounded by one arch of the curve y=sin sin mx(m>0) and the x -axis is

The area bounded by the curve y = sin x , x in [0,2pi] and the x -axis is equal to:

Area bounded by the curve y = sin^(-1)x , the X-axis and the line 2x = 1 is

The area bounded by the curve y = sin x, pi le x le 2 pi and the x-axis is

Find the area bounded by the curve y=-3|x|+2 and x -axis

The area bounded by the curve y = sin x , x in [0,2pi] and the x-axis is equal to

Consider the curve C: y = sin 2x - sqrt(3)|sinx|, C cuts the x-axis at (a,0) , x in (-pi, pi) . A_(1) : The area bounded by the curve C and the positive x-axis between the origin and the line x = a . A_(2) : The area bounded by the curve C and the negative x-axis between the line x = a and the origin. Prove that A_(1) + A_(2) +8A_(1) A_(2) = 4 .

The area bounded by the curve y=|cos x-sin x|,0<=x<=(pi)/(2) and above x - axis is

Find the area bounded by the curve y=x sins-axis in the interval 0<=x<=2 pi

Find the area bounded by the y-axis and the curve x = e^(y) sin piy, y = 0, y = 1 .