What will be `K_(p) " for the reaction" 2 NOCl (g) to 2 NO(g) + Cl_(2) (g) " at 1000 K? " K_(c) " at 1000 K is " 3*75 xx 10^(-6).`

For the reaction : CO(g)+Cl_(2)(g)hArr COCl_(2)(g) the K_(p)//K_(c ) is equal to :

For the reaction: 2NOCl(g) hArr 2NO(g) +Cl_(2)(g), K_(c) at 427^(@)C is 3xx10^(-6) L mol^(-1) . The value of K_(p) is

For the reaction: NOCl(g) hArr 2NO(g) +Cl_(2)(g), K_(c) at 427^(@)C is 3xx10^(6) L mol^(-1) . The value of K_(p) is

At 1000 K, if the equilibrium constant K_(p) for the reaction. 2NOCl(g)hArr2NO(g)+Cl_(2)(g) is 4.157xx10^(-4) bar, the K_(c) (in mol L^(-1) ) is (R = 0.083 L bar K^(-1)mol^(-1) )

For the reaction, 2NOCl(g)hArr2NO(g)+Cl_(2)(g) the value of K_(c)=3.75xx10^(-6) at 1069K. Calculate K_(p) .

For the reaction: NOCl(g) hArr 2NO(g) +Cl_(2)(g), K_(c) at 427^(@)C is 2xx10^(6) L mol^(-1) . The value of K_(p) is