A graph between `log t_((1)/(2))` and log a (abscissa), a being the initial concentration of A in the reaction For reaction `Ato`Product, the rate law is :

Following is the graph between log t_(1//2) and log a ( a initial concentration) for a given reaction at 300K Find the order of reaction.

Following is the graph between log t_(1//2) and log a ( a initial concentration) for a given reaction at 27^(@)C . Find the order of reaction.

Following is the graph between log T_(50) and log a ( a = initial concentration) for a given reaction at 27^(@)C . Hence order is

Following is the graph between log T_(50) and log a ( a = initial concentration) for a given reaction at 27^(@)C . Hence order is

Following is the graph between log T_(50) and log a (a = initial concentration) for a given reaction at 27^(@)C . Hence, order is

The graph between log t_(1//2) and log a at a given temperature is Rate of this reaction will …….with passage of time

The graph between log t_(1//2) and log a at a given temperature is Rate of this reaction will …….with passage of time

For a reaction A rarr Products, a plot of log t_(1/2) ,versus log a is shown in figure. If the initial concentration of A is represented by a ,the order of the reaction is:-