A force of `3x^(2)-2x+5` acts on a body of mass 5 kg and displaces it from `x=0` to `x=4`m. What is the work done by the force?

A position dependent force F=7-2x+3x^(2) acts on a small body of mass 2 kg and displaced it from x=0 to x=5m . Calculate the work done in joule.

A position dependent force F=7-2x+3x^(2) acts on a small body of mass 2 kg and displaced it from x=0 to x=5m . Calculate the work done in joule.

A position dependent force f =(7-2x+3x^2) N acts on a body of mass 2 kg and displaces it from x=0 to x=5 m. Determine the amount of work done in joule.

A positon dependent force , F=8-4x+3x^(2)N acts on a small body of mass 2 kg and displaces it from x=0 to x=5 m. The work done in joule is

A positon dependent force , F=8-4x+3x^(2)N acts on a small body of mass 2 kg and displaces it from x=0 to x=5 m. The work done in joule is

A position dependent force f=(7-2x+3x^(2))N acts on a small body of mass 2 kg and displaces it from x=0 " to " x=5m . Work done is