The complex ion `[Cu(NH_3)_4]^(2+)` is

The complex ion [Cu(NH_3)_4]^(2+) has:

Ammonia forms the complex ion [Cu(NH_3)_4]^(2+) with copper ions in alkaline solutions but not in acidic solution. The reason for this is

Ammonia forms the complex ion [Cu(NH_3)_4]^(2+) with copper ions in alkaline solutions but not in acidic solutions. The reason is

For a general reaction given below, the value of solubility product can be given us {:(A_(x)B_(y),=xA^(+y),+yB^(-x)),(a,0,0),(a-s,xs,ys):} K_(sp)=(xs)^(x).(ys)^(y) (or) K_(sp)=x^(x)y^(y) (S)^(x+y) Solubility product gives us not only an idea about the solubility of an electrolyte in a solvent but also helps in explaining concept of precipitation and calculation [H^(+)] ion, [OH^(-) ] ion. It is also useful in qualitative analysis for the idetification and separation of basic radicals What is the molar solubility of Cu(OH)_(2) , in 1.0 M NH_(3) if the deep blue complex ion [Cu(NH_(3))_(4)]^(2+) is formed. The K_(sp), of Cu(OH)_(2) , is 1.6xx 10^(-19) and K_(3) , of [Cu(NH_(3))_(4) is 1.1 xx 10^(13)

The complex ion [Cu(NH_(3))_(4)]^(2+) has