The radius of curvature of a metre gauge railway line at a place where the train is moving at `36km //h` is 50 m .If there is no side thrust on the rails , then the elevation of the outer rail above the inner rail will be `(g=10m//s^(2))`

The radius of curvature of a railway line at a place when the train is moving with a speed of 36kmh^(-1) is 1000m, the distance between the two rails being 1.5m. The elevation of the outer rail above the inner rail is

The radius of curvature of a railway line at a place when the train is moving with a speed of 36 kmh^(-1) is 1000 m, the distance between the two rails being 1.5 metre. Calculate the elevation of the outer rail above the inner rail so that there may be no side pressure on the rails.

The radius of curvature of a railway track at a place where the train is moving at a speed of 72 km h^-1 is 625 m.The distance between the rails is 1.5 m.Find the angle and the elevation of the outer rail so that there may be no side pressure on the rails. (g=9.8 m s^(-2)) .

The radius of curvature of a railway track at a place where the train is moving at a speed of 72 kmh^(-1) is 625m . The distance between the rails is 1.5 m. Find the angle and the elevation of the outer rail so that there may be no side pressure on the rails, Take g = 9.8 ms^(-2) .

The radius of curvature of railway track at a place where the train is moving at a speed of 72km h^(-1) is 625m The distance between the rails is 1.5m Find the angle and the elevation of the outer rail so that there may be no side pressure on the rails Take g = 9.8ms^(-2) .

The radius of curvature of a railway line at a place is 40000m.the train is running at 20 m s^-1 .the distance between the two rails is 1.5 m.Find the elevation of the outer rail over the inner one so that the train may be able to run safely.

A train is moving with a speed of 20 m/s at a place where the radius of curvature of the railway line is 1500 m. Calculate the distance between the rails if the elevation of the outer rail above the inner rail is 0.042 m ?

A train is moving at 20 m//s on a railway track of radius of curvature 1600 m. If the distance between two tracks is1.8 m, then the elevation of the outer track above the inner track will be

The angle of banking for a railway track is given by theta =sin ^(-1) ((1)/(16)) . If it is a metre gauge railway line , then the elevation of the outer rail above the inner rail is

A train is running at 20 m/s on a railway line with radius of curvature 40,000 metres. The distance between the two rails is 1.5 metres. For safe running of train the elevation of outer rail over the inner rail is (g=10m//s^(2))