" A body is projected vertically up and the total distance travelled by it is 'S' Then total time of flight will be "

In the previous question, the total distance traveled is

A body is projected vertically upward with speed 40m/s. The distance travelled by body in the last second of upward journey is [take g=9.8m/s^(2) and neglect eggect of air rresistance]:-

A body is projected vertically upward with speed 40m/s. The distance travelled by body in the last second of upward journey is [take g=9.8m/s^(2) and neglect of air resistance]:-

A body is projected vertically upward with speed 40m/s. The distance travelled by body in the last second of upward journey is [take g=9.8m/s^(2) and neglect eggect of air rresistance]:-

If a ball is projected vertical upward from ground such that total distance traveled is 3.6 times of distance travel by the ball in 1​^(st) ​ second, then find time of flight of ball ?

A body when projected vertically up from ground clovers a total distance D during the time of its flight t. If there were no gravity. The distance covered by it during the same time is equal to

A body when projected vertically up from ground clovers a total distance D during the time of its flight t. If there were no gravity. The distance covered by it during the same time is equal to

A body is projected vertically up with a speed of 20ms^(-1) .The distance travelled by it in "3" seconds it (g=10ms^(-2))