Activities of three radioactive substances A, B and C are represented by the curves A, B and C, in the figure. Then their half- lives `T_(1/2)(A): T_(1/2) (B): T_(1/2)(C )` are in the ratio :

Activity of a radioactive substance is R_(t) at time t_(1) and R_(2) at time t_(2)(t_(2)gtt_(1)) . Then the ratio (R_(2))/(R_(1)) is

If 2.0 g of a radioactive substance has t_(1//2) of 7 days , the half life of 1 g sample is

Activity of a radioactive substance is A_(1) at time t_(1) and A_(2) at time t_(2)(t_(2) gt t_(1)) , then the ratio of f (A_(2))/(A_(1)) is:

Three rods AB, BC and BD having thermal conductivities in the ratio 1:2:3and length in the ratio 2:1:1 are joined as shown in figure . The ends A , C and D are at temperature T_(1), T_(2) and T_(3) respectively . Find the temperature of the junction B . Assume steady state .

Activity of a radioactive substance is R_(1) at time t_(1) and R_(2) at time t_(2) (t_(2) gt t_(1)) then the ratio (R_(2))/( R_(1)) is :

The activity of a radioactive substance is R_(1) at time t_(1) and R_(2) at time t_(2)(gt t_(1)) . Its decay cosntant is lambda . Then .

The activity of a radioactive substance is R_(1) at time t_(1) and R_(2) at time t_(2)(gt t_(1)) . Its decay cosntant is lambda . Then .

In the P - V diagram, the point B and C correspond to temperatures T _(1) and T_(2) respectively. State relationship between T_(1) and T_(2).