When a body of mass M slides down an inclined plane of inclination `theta`, having coefficient of friction `mu` through a distance s, the work done against friction is :

A block of mas m begins to slide down on an inclined plane of inclination theta . The force of friction will be

A block of mass 2 kg, slides down a rough inclined plane of length I rn and inclination 60°. The coefficient ofkinetic friction is 0.4. What is the work done against friction, when it slides from the top to the bottom?

A small mass slides down an inclined plane of inclination theta the horizontal the coefficient of friction is m = mu_(0)x , where x is the distance by the mass before it stops is .

A block of mass m slides down an inclined plane of inclination theta with uniform speed The coefficient of friction between the block and the plane is mu . The contact force between the block and the plane is .

A body of mass m slides down a rough plane of inclination alpha . If mu is the coefficient of friction, then acceleration of the body will be

A body of mass m slides down a rough plane of inclination alpha . If mu is the coefficient of friction, then acceleration of the body will be

A block of mass m slides down an inclined plane of inclination theta with uniform speed. The coefficient of friction between the block and the plane is mu . The contact force between the block and the plane is

A block of mass m slides down an inclined plane of inclination theta with uniform speed. The coefficient of friction between the block and the plane is mu . The contact force between the block and the plane is

A small mass slides down an inclined plane of inclination theta with the horizontal the coefficient of friction is mu = mu_(0)x , where x is the distance through which the mass slides down. Then the distance covered by the mass before it stops is