`(x^(2))/(100)+(y^(2))/(400)=1`

Find the coordinats of the foci, the vertice ,eccentricity and length of latus rectum of ellipse (x^(2))/(100) + (y^(2))/(100) = 1 .

Find the eccentricity of the ellipse (i) (x^(2))/(16)+(y^(2))/(9)=1 (ii) (x^(2))/(64)+(y^(2))/(36)=1 (iii)25x^(2)+4y^(2)=100

If x% of y is equal to z what percent of z is x?(y^(2))/(100) b.(y)/(100^(2)) c.(100)/(y) d.(100^(2))/(y)

x ^ (2) - (y ^ (2)) / (100)

Factorize (i) (x^2-(y^2)/(100)) (ii)(100-9x^2) (iii)(49x^2-(1)/(4))

The major and minor axis of the ellipse 400x^(2)+100y^(2)=40000 respectively are

Then equation of auxiliary circle of the ellipse 16x^(2)+25y^(2)+32x-100y=284 is (A)x^(2)+y^(2)+2x-4y-20=0 (B) x^(2)+y^(2)+2x-4y=0 (C) (x+1)^(2)+(y-2)^(2)=400(D)(x+1)^(2)+(y-2)^(2)=225

If sin^(-1) x +sin^(-1)y +sin^(-1) z =(3pi)/(2) , then find the value of x^(100) +y^(100) +z^(100) -(9)/(x^(101)+y^(101)+z^(101)) .

If sin^(-1)x+sin^(-1)y+sin^(-1)z=(3pi)/2 then the value of x^(100)-y^(100)-z^(100)-12/(x^(101)-y^(101)-z^(101))=