Home
Class 12
MATHS
If one of the diameters of the circle, g...

If one of the diameters of the circle, given by the equation, `x^2+y^2-4x+6y-12=0` , is a chord of a circle S, whose centre is at `(-3,""2)` , then the radius of S is :

Promotional Banner

Similar Questions

Explore conceptually related problems

If one of the diameter of the circle , given by the equation , x^(2) + y^(2) - 4x + 6y - 12 = 0 , is a chord of a circle S , where centre is at (-3,2) , then the radius of S is

In one of the diameters of the circle, given by the equation x^(2) + y^(2) - 4x + 6y - 12 = 0 , is a chord of a circle S , whose center is at (-3 , 2) , then the radius of S is

If one of the diameters of the circle, given by the equation x ^(2) + y^(2) + 4x + 6y -12 =0, is a chord of a circle S, whose centre is (2,-3), the radius of S is

If one of the diameters of the circle, given by the equation x ^(2) + y^(2) + 4x + 6y -12 =0, is a chord of a circle S, whose centre is (1,-3), the radius of S is

If one of the diameters of the circle, given by the equation x^(2)+y^(2)+4x+6y-12=0 , is a chord of a circle S , whose centre is (2,-3) , the radius of S is

If one of the diameter of the circle, given by the equation x^(2)+y^(2)+4x+6y-12=0 , is a chord of a circle S, whose centre is (2,-3), the radius of S is

If one of the diameters of the curve x^(2)+y^(2)-4x-6y+9=0 is a chord of a circle with centre (1,1), the radius of this circle is

If one of the diameters of the curve x^2+y^2-4x-6y+9=0 is a chord of a circle with centre (1,1), then the radius of this circle is

If one of the diameters of the circle x^2+y^2-2x-6y+6=0 is a chord to the circle with centre (2,1), then the radius of the circle is

If one of the diameters of the circle x^2+y^2-2x-6y+ 6 = 0 is a chord to the circle with centre (2, 1), then the radius of circle is: