At 300 K and 1 atm, 15 mL of gaseous hydrocarbon requires 375 mL air containing 20% `O_(2)` by volume for complete combustion. After combustion the gases occupy 330 mL. assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is-

At 300 K and 1 atm, 15 mL of a gaseous hydrocarbon requires 375 mL air containing 20% O_(2) by volume for complete combustion. After combustion, the gases occupy 330 mL . Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is

At 300 K and 1 atm, 15 mL of a gaseous hydrocarbon requires 375 mL air containing 20% O_(2) by volume for complete combustion. After combustion, the gases occupy 330 mL . Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is

500mL of a hydrocarbon gas burnt in excess of oxygen yielded 2500 mL of Co_2 and 3.0 liter of water vapour (all volumes measured at the same temperature and pressure). The formula of the hydrocarbon is :

500 ml of a hydrocarbon gas burnt in excess of oxygen yields 2500 ml of CO_2 and 3 litres of water vapours. All volume being measured at the same temperature and pressure. The formula of the hydrocarbon is :